B.E-B.E Electronics and Communication Engineering Digital Systems (Sathyabama University, Chennai, Tamil Nadu-2011)
Monday, 19 August 2013 07:20Duraimani
(Established under section 3 of UGC Act,1956)
Course & Branch :B.E - P-ECE
Title of the Paper :Digital Systems Max. Marks:80
Sub. Code :SECX1002 (2010-11) Time : 3 Hours
Date :03/12/2011 Session :FN
PART - A (10 x 2 = 20)
Answer ALL the Questions
1. Why Gray Code is called a reflective code?
2. Expand A’ + B’ to minterms.
3. What is a multi-level gate network?
4. Realize f = C’+AB’+A’B using NAND gates.
5. Draw a two bit magnitude comparator.
6. Distinguish between a decoder and a de-multiplexer
7. State some applications of shift registers.
8. What is a State diagram?
9. Why ECL logic is faster than TTL?
10. State the parameters used to characterize logic families.
PART – B (5 x 12 = 60)
Answer All the Questions
11. (a) Perform the following conversions:
(i) A0F9.0EB16 TO DECIMAL
(ii) 756.6038 TO HEX.
(iii) 110101.1010102 TO OCTAL
(b) Do the following arithmetic:
(i) Add 6E16 and C516
(ii) Subtract 7B16 from C416
(iii) Subtract 5D16 from 3A16
(or)
12. Discuss the properties of Boolean algebra.
13. Reduce using K- map both in POS and SOP forms :
F = ∑m (0,2,4,6,7,8,10,12,13,15)
(or)
14. Obtain the minimal POS expression using the tabular method for:
f (v,w,x,y,z) = ∑m (0,4,12,16,19,24,27,28,29,31)
15. (a) Implement the following function with a 8 X 1 multiplexer:
F(A,B,C,D) = ∑(1,3,4,11,12,13,14,15). (7)
(b) Write short notes on Priority encoder. (5)
(or)
16. Realize a BCD adder using full adders and explain.
17. (a) Explain the concept of master slave using two D latches and an inverter.
(b) Brief about State reduction and State assignment.
(or)
18. (a) Explain the four stage switch tail ring counter.
(b) Convert a JK Flip Flop to a T Flip Flop.
19. (a) Compare the characteristics of different logic families. (8)
(b) Draw the circuit diagram of a 3-input I2L NOR Gate. (4)
(or)
20. Implement the following two functions using PLA:
F1(A,B,C) = ∑(0,1,2,4)
F2(A,B,C) = ∑(0,5,6,7)
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