Indian Institue of Management 2008 COMMON APTITUDE TEST (CAT ) - Question Paper
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Directions for ques. 10 and 11:
Let f(x) = ax2+bx+c, where a,b and c are certain constants and a?0. It is known that f(5) = -3f(2) and that three is a root of f(x) =0
10. What is the other root of f(x) = 0?
(1) -7 (2) -4 (3) two (4) six (5) cannot be determined
11. What is the value of a+b+c?
(1)9 (2) 14 (3) 13 (4) 37 (5) cannot be determined
12. the number of common terms in the 2 sequences 17,21,25,….417 and 16, 21, 26,….. 466 is
(1) 78 (2) 19 (3) 20 (4) 77 (5) 22
13. Let f(x) be a function satisfying f(x)f(y) = f(xy) for all real x,y. If f(2) = 4, then what is the value of f(1/2)?
(1) 0 (2) ¼ (3) ½ (4) one (5) cannot be determined.
14. If the roots of the formula x3-ax2+bx-c=0 are 3 consecurive integers, then what is the smallest possible value of b?
(1) -1/v3 (2) -1 (3) 0 (4) one (5) 1/v3
Directions for ques. 15 and 16:
Mark (1) if Q can be answered from A alone but not from B alone.
Mark (2) if Q can be answered from B alone but not from A alone.
Mark (3) if Q can be answered from A alone as well as from B alone.
Mark (4) if Q can be answered from A and B together but not from any of them alone.
Mark (5) if Q cannot be answered even from A and B together.
In a single elimination tournament, any player is eliminated with a single loss. The tournament is played in multiple rounds subject to the subsequent rules:
(a) if the number of players, say n, in any round is even, then the players are grouped in to n/2 pairs. The players in every pair play a match against every other and the winner moves on to the next round.
(b) If the number of players, say n, in any round is odd, then 1 of them is provided a bye, that is he automatically moves on to the next round. The remaining (n-1) players are grouped into (n-1)/2 pairs. The players in every pair play amatch against every other and the winnermoves on to the next round. No player gets more than 1 bye in the entire tournament.
| Earning: Approval pending. |
