Kerala University 2005 B.E Engineering Entrance - Question Paper

Chemistry
1. Identify the product in the subsequent sequence
3,4,5-tribromoaniline ( )
( ) three two 2
1
H PO
diazotization ?
A. 3,4,5-tribromobenzene
B. 1,2,3-tribromobenzene
C. 2,4,6-tribromobenzene
D. 3,4,5-tribromonitrobenzene
E. 3,4,5-tribromophenol
Ans: B
2. Among the amines a) six five two C H NH b) three two CH NH c) (CH ) NH three two d)(CH ) N three 3 the order of
basicity is
A. a < b < d < c
B. d < c < b < a
C. a > b > c > d
D. b < c < d < a
E. d < c < b< a
Ans: A
3. The number avg. molecular mass and mass avg. molecular mass of a polymer are
respectively 30,000 and 40,000. The poly dispersity index of the polymer is
A. < 1
B. > 1
C. 1
D. 0
E. –1
Ans: B
4. In biological systems, the RNA molecules direct the synthesis of specific proteins, which are
characteristic of every type of organism. This process is known as
A. Transcription
B. Mutation
C. Replication
D. Translation
E. Flocculation
Ans: D
5. Pick up the accurate statement
A. CO which is major pollutant resulting from the combustion of fuels in automobiles
plays a major role in photochemical smog
B. Classical smog has an oxidizing character while the photochemical smog is reducing
in character
C. Photochemical smog occurs in day time whereas the classical smog occurs in early
morning hours
D. During formation of smog the level of ozone in the atmosphere goes down
E. Classical smog is good for health but not photochemical smog
Ans: C
6. In Antarctica ozone depletion is due to the formation of subsequent compound
A. Acrolein
B. Peroxy acetyl nitrate
C. SO2 and SO3
D. Chlorine nitrate
E. Formaldehyde
Ans: D
7. 100 g CaCO3 is treated with one litre of one N HCl. What would be the weight of CO2 liberated
after the completion of the reaction?
A. 5.5g
B. 11 g
C. 22 g
D. 33 g
E. 44 g
Ans: C
8. The relationship ranging from the energy E1 of the radiation with wavelength 8000
?A
and the
energy E2 of the radiation with a wavelength 16000
?
A is
A. one two E = 6E
B. one two E = 2E
C. one two E = 4E
D. one two 2 E
E = 1
E. one two E = E
Ans: B
9. If the molecule of HCl were totally polar, the expected value of dipole moment is 6.12D
(debye), but the experimental value of dipole moment was 1.03D. compute the percentage
ionic character
A. 17
B. 83
C. 50
D. Zero
E. 90
Ans: A
10. Which 1 of the subsequent molecules has the smallest bond angle?

Earning:   Approval pending.