Periyar University 2008 B.E Electronics

1) If log 0.317=0.3332 and log 0.318=0.3364 then obtain log 0.319 =

Sol: provided log 0.317=0.3332 and log 0.318=0.3364

Then

Log 0.319=log0.318+ (log0.318-log0.317)

=0.3396





2) A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there?

Sol: provided x= two kg Packs

y= one kg packs



=> x + y = 150 .......... Eqn 1

=> 2x + y = 264 .......... Eqn 2

On solving these 2 equations

x = 114


By using formula 1

114 + y = 150

=> y = 36



=>Number of two kg Packs = 114.





3) My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?

a) 6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00

Sol: (Hint: Every one deg longitude is equal to four minutes. If west to east add time else subtract time)

Ans: 8:00





4) A Flight takes off at two A.M from northeast direction and travels for 11 hours to reach the destination, which is in northwest direction. provided the latitude and longitude of source and destination. obtain the local time of destination when the flight reaches there?


Ans: seven AM (or) one PM





5) A moves three kms east from his starting point. He then travels five kms north. From that point he moves eight kms to the east. How far is A from his starting point?

Ans: 13 kms





6) Aeroplane is flying at a particular angle and latitude, after a few time latitude is provided. (8 hrs later), u r asked to obtain the local time of the place.



7) An Aeroplane begins from A (SOME LATITUDE IS provided ACCORDING TO PLACE).At two AM local time to B (SOME LATITUDE). Traveling time is 10 Hours. What is the local time of B when it reaches B?



8) A plane moves from 9°N40°E to 9°N40°W. If the plane begins at 10 am and takes eight hours to reach the destination, obtain the local arrival time.


Sol: Since it is moving from east to west longitude we need to add both

Ie, 40+40=80

Multiply the ans by 4

=>80*4=320min

Convert this min to hours i.e., 5hrs 33min

It takes 8hrs totally. So 8-5hr 30 min=2hr 30min

So the ans is 10am+2hr 30 min

Ans: 12:30 it will reach





9) The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent?

Earning:   Approval pending.