Karnataka State Open University (KSOU) 2009 B.A Psychology (RSS) ( 1 ) - sic Psychological Process - /e ( Code: A 121 - O - 2) - Question Paper
Illlllllllllllllllllll A 121 - O - 2
First Year B.A. Examination, May/June 2009
(RSS)
PSYCHOLOGY (Course - I)
Basic Psychological Processes
Date : 31-5-2009 Max. Marks : 100
Time : 2.00 p.m. to 5.00 p.m.
SECTION - A
Answer any three of the following : (12x3=36)
1. Explain the scope of psychology.
2. Explain the behaviouristic and humanistic approaches to psychology.
3. What are sensory organs ? Explain the structure and functions of the eye.
4. Define learning. Explain spontaneous recovery and transfer of training.
5 . What is motivation ? Explain biological motives.
6. What is reasoning ? Explain the problem solving approaches.
SECTION - B
Answer any two of the following : (9x2=18)
1. What is intelligence ? Explain the distribution of intelligence in normal population.
2. What is emotion ? Explain the physiological changes in emotion.
3 . What is personality ? Explain the determinants of personality.
4. What is thinking ? Explain the imagery and cognitive maps.
SECTION - C
Write short notes on any 4 (four) of the following : (4x4=16)
1. Psychology 2. Genes
3. Perception 4. Memory
5. Nervous system 6. Interview.
SECTION - D
I. Briefly describe the plan, procedure, precautions and other details for the following experiment : (10x1=10)
Set on attention OR
II. Answer the following : (10x1=10)
Following results are obtained from distribution of learning periods. Discuss and draw conclusions.
|
SL. NO. |
1 |
2 |
3 |
4 |
5 |
6 |
|
Subject |
A |
B |
C |
D |
E |
F |
|
Massed Method |
4 |
5 |
7 |
3 |
5 |
6 |
|
Spaced Method |
7 |
4 |
9 |
5 |
7 |
7 |
OR
Following results are obtained from Muller-Lyer illusion.
|
SL. NO. |
1 |
2 |
3 |
4 |
5 |
|
Subject |
A |
B |
C |
D |
E |
|
Ascending Series |
9 |
10 |
12 |
13 |
11 |
|
Descending Series |
14 |
13 |
16 |
14 |
15 |
Note : Standard line length is 15 cm.
III. Calculate mean, median and mode for the data given below : (10x1=10)
12, 15, 11, 13, 14, 12, 11, 10, 12 OR
Classify the following data into a frequency table.
19, 28, 30, 31, 36, 41, 45, 46, 47, 25 41, 48, 20, 32, 21, 37, 24, 36, 47, 28 35, 32, 43, 42, 50, 50, 49, 35, 37, 36
h Cd)rf>rfd bdb dJdAA ido:
1. db>e<a>d d&Cbb do.
2. db>e<a>d0ddF> dbdb ddss dArAsb do&.
(12x3=36)
3. ;oderf>>oAA>d)d) ? 5 d dbdb saCbrAsb do&.
4. 5Q5Cbb d>&. dbd$5 dbdb 505> dArdraCbb do.
=i. erf 1 -0 =i.
5. edJedra qorfdeb c 5 (d>oeo5) ddraAb do.
6. de qoddeb c ;db;srdos3d dArAb do.
- >>A
h Cd)rf>rfd> qdb d,dA>A ido :
(9x2=18)
1. zobQ dd qoddeb c ;>dW &dQ zobQddCb ddraCbb do.
Q _D a CO Q _D <
2. ;odeA (o>d>de) qoddeb c ;odeAdo>Abd d>oeo5 wdcsdyAb do.
3. d.ad, qoddeb c d.ad,rf $E3Fd5Asb do.
a-> c3 a-c c3 1 <
4. fd>ei qorfdeb c osd dbdb 5Ab<ado.
& - >>A
h Cd)rf>rfd> ssca <adCb5 oo d wdbo :
(4x4=16)
1. dbe<a>d
2. doddsAyb
|
3. d,d.5>rfbdd J ?\ r. >, * |
 |
 |
|
;>Cbb 5Q5CbQ eoddd&Cb d>d,. =i. C-O eJ aJ -J |
h tood) oti sb3b 3dy) djataeraorf woari gdrtfrfb Srarabrtfrfb staa
C C
|
3r. HO& -J |
1 |
2 |
3 |
4 |
5 |
6 |
|
(sjataerar) |
A |
B |
C |
D |
E |
F |
|
4 |
5 |
7 |
3 |
5 |
6 | |
|
7 |
4 |
9 |
5 |
7 |
7 |
ero>
h titfftrf 4>teo2d) docd' d)jue djotaeraorf woarf gdTtfrfbf&, Srarobrtfrfb tites.
|
o |
l |
2 |
3 |
4 |
5 |
|
sjotaeror |
A |
B |
C |
D |
E |
|
fdtaera |
9 |
10 |
12 |
13 |
11 |
|
edtae) |
14 |
13 |
16 |
14 |
15 |
: dWs1 rdb idd) 15 Cm grf.
CO
III. h titfftrf dsaorr toao, dboti db3b wdbtfaoti (eQdJ) drfotiodb&SbO. (10x1=10)
12, 15, 11, 13, 14, 12, 11, 10, 12 e$ro>
h titfftrf dsaortfrfb drrdS (drarod) dbrfb wdDQ.
_o t v y <lLd eJ t
19, 28, 30, 31, 36, 41, 45, 46, 47, 25 41, 48, 20, 32, 21, 37, 24, 36, 47, 28 35, 32, 43, 42, 50, 50, 49, 35, 37, 36
|
Attachment: |
| Earning: Approval pending. |
