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Calicut University 2007 Certification TES THE PRINCETON REVIEW CET 1 - Question Paper

Tuesday, 07 May 2013 08:50Web
41.(d) 42. (d) 43. (d) 44. (c) 45. (b) 46. (c) 47. (a) 48. (a) 49. (d) 50.(b)


part 2
1. (c) 2. (b) 3. (c) 4. (a) 5. (c) 6. (d) 7. (c) 8. (a) 9. (d) 10. (b)
11. (a) 12. (a) 13. (c) 14. (b) 15. (c) 16. (b) 17. (b) 18. (b) 19. (c) 20. (c)


part 3
1. (c) 2. (c) 3. (d) 4. (d) 5. (c) 6. (c) 7. (a) 8. (d) 9. (a) 10. (c)
11. (c) 12. (b) 13. (d) 14. (d) 15. (c) 16. (d) 17. (c) 18. (c) 19. (c) 20. (d)
21. (c) 22. (c)


part 4

1. (c) 2. (d) 3. (b) 4. (a) 5. (b) 6. (d) 7. (d) 8. (d) 9. (b) 10. (c)
11. (c) 12. (b) 13. (c) 14. (b) 15. (a) 16. (d) 17. (b) 18. (c) 19. (a) 20. (d)
21. (d) 22. (b) 23. (b) 24. (a) 25. (d) 26. (b) 27. (b) 28. (b) 29. (a) 30. (c)
31. (c) 32. (a) 33. (c) 34. (d) 35. (d) 36. (d) 37. (a) 38. (c) 39. (b) 40. (d)
41. (d) 42. (c) 43. (b) 44. (d) 45. (b) 46. (a) 47. (c) 48. (d) 49. (c) 50. (b)
51. (d) 52. (d) 53. (d) 54. (c) 55. (b) 56. (c) 57.(c) 58.(b) 59.(d) 60.(c)
61.(a) 62.(c) 63.(b) 64.(c) 65.(b) 66. ( a)

SOLUTION

part 4
1. c

2. d

3. c From clues IV & VI we conclude that F – G – H are the recruitment agents that should
be included. Hence only 1 combination is possible.

4. a
5. b From solutions 68 & 69 we know that F, G and B all can go with C, hence right ans

should be (b).

Directions for six to 11: Refer to the subsequent table for the subsequent solutions.

The subsequent table provide the moves that can be made for the mentioned conditions. The
underlined positions indicate your position after nth move.
Move Minimum
Score
Maximum
Score
Reaching 5
O’clock
0th one = one 1 = one 1
1st seven – four = three 12 – two = 10 12
2nd one – four = three 11 – two = nine 11 / 6
3rd two = two - 5
4th - - -
Total three 20 -

6. d

7. c

8.d By moving a step anticlockwise in the 1st move, you reach at 12 O’clock. From here you
can reach
a 10’O Clock through 12 – 11 - 10
b five ‘O clock through 12 – six – 5
c seven ‘O Clock through 12 – six – 7.
But you cannot reach six ‘O Clock. Hence (4).

9. b

10. c Your mother’s husband ? your dad. Your father’s sister ? your aunt. So, the lady’s
aunt is the man’s aunt ? the man and the lady are brother and sister.

11. c M is the maternal uncle of R means m is the brother of R‘s mother (say K) i.e., M + K – R.


Direction for 12 to 13: Refer to the subsequent info for the subsequent solutions.
We are provided that A visited at eight O’clock. Now from III we conclude that A visited at 8
p.m. Now from I we concluded that B has to visit at nine a.m. otherwise nobody will be able
to visit in ranging from A & B. Now if D were to visit at 11 p.m. then condition IV will get
violated hence we concluded that D visited at 11 a.m. and C visited at 10 p.m. From here
all the ques. are answered.

12. b

13. c


Directions for 14 to 19: Refer to the subsequent info for the subsequent solutions.
The ratio of the values of Dollar: Pound: DM, for July month are computed as beneath.
Table of exchange rate fluctuation ranging from DM/Pound during the sex months, can be
computed as,
Dollar (Do) Pound (Po) DM Month
1.6 1
1 1.5
1.6 one 2.4 July

Similar approach is applied to arrive at subsequent table.
Do Po DM Month
1.64 one 2.4928 Aug.
1.62 one 2.3976 Sep.
1.58 one 2.2752 Oct.
1.54 one 2.0944 Nov.
1.5 one 2.085 Dec.
From this all the ques. can be answered.


14. c Directly looking at the table.

15. a Directly looking at the table.

16. d To purchase maximum number of pounds,
Pounds : DM ratio should be maximum or
DM : Pounds ratio should be minimum.

17. b The cost per kg of tea is Rs. 64. Therefore, the cost per tonne of tea is 64 X 1000 =
Rs. 64,000.
100 mn = Rs. 48 X 100 mn = Rs. 4800 mn. Rs. 4800 X 106
No. of tones of tea that needs to be exported =
64000
4800000000
= 75000 tonnes.

18. c From the table it is clear that 10 Pounds = 24.928 DM = Rs. 747.84 ? Rs. 747.80.


19. a Highest percentage change was in Nov. – Dec. and was equal to
1 54
0 04
.
.
X 100 = 2.60%


20.d Because the minority might consist of thousand of people, the opposition might not be
inconsistent with the speaker’s remarks.

21. b

22. b If 20% work in the tech. level and within, that means 80% are in the outer 2 layers.
? 8% of 355 = 284.
From this, subtract the number of people in the peripheral layer (54), to get the ans =
230.

23. a The number must be equal to or more than 36 considering the three security personnel rule.
? options b and d are invalid.
Out of the 110 people there are already 54 in the peripheral level, thus there cannot be
more than 56 in the security level. This eliminates option c of 58, leaving 1 option a

24. d A drop of 12 people in peripheral is equivalent to 50% of the complete lay-offs, which
then must be 12 x two = 24, which is 15% of the original population, which must be:
24/0.5 = 160. Hence, d

25. b The total number of people who do not need security clearance are 54 + 48 = 102.
? Percentage of people who do need security clearance =
360
360 ? 102
= 100% ? 72%.
Hence b


Q. 26 – 28. From condition # one and # 2, either
I. Mr. Gupta won 1 game, Mrs. Gupta won 1 game, and Mr. Sharma won one
game; or
II. Mr. Gupta won 2 games and Mrs. Gupta won 1 game; or
III. Mr. Gupta won 2 games and Mrs. Sharma won 1 game.
If I is correct, then : Form (3), Mr. Sharma beat Mrs. Sharma in the 1st game. Then, only
Mr. Sharma could have lost to Mr. Gupta or Mrs. Gupta in the 2nd game. Then, from
(3), no 1 could have played against the last winner in the last game. So, I is not accurate.
II cannot be accurate from (3).
So, III is accurate. If Mrs. Sharma won the 1st game, then she beat Mr. Sharma inthat
game, from (3). But then, from (3), no 1 could have played against Mr. Gupta in the
second game. So, Mr Gupta won the 1st game against Mrs. Gupta, from (1). Then, Mr.
Gupta beat Mr. Sharma in the 2nd game. The Mrs. Sharma beat Mr. Gupta in the third
game. So, only Mrs. Sharma did not lose a game.


26. b 27. b 28. a

Qs. 29 – 33

29. d 30. c 31. a 32. b 33. c

Qs. 34 – 36

34. b 35. b 36. d 37. a 38. c 39.b 40. d

41. 42. c 43. b 44. d 45.c 46. a

47-48. The 2nd resident always speaks truth (so, not a govt. official) 1st speaker may speak
truth (IS not & denies being a govt. official) or may tell a lie (is a govt. official but denies
being one) – in either case denying being a govt. official. If 1st resident speaks truth the
third 1 tells a lie and vice-versa.

47. c 48. d

49. (3) History of Modern Europe (HME) + American History (AH) = 90 + 90 = 180, but there
are only 120 students. Thus, at lowest 60 students opted both of the above subjects. HME
and AM + Ancient Indian History (AIH) = 60 + 105 = 165. Thus, again, as there are only
120 students, at lowest 45 would have taken all 3 of above. Using the identical logic, (45 +
105) – 120 = 30 students at lowest would choose all the 4 subjects.

50. b 51. d

52.d By conditions (vi) and (vii) together, (4) is necessarily actual. Hence, (d).

53.d If E is midway ranging from B and C, then the distance ranging from B and E is ¼ mile and
ranging from E and C is ¼ mile. Then: (a) is actual by condition (iii); (b) is actual by conditions
and (ii) and (iii); (c) is actual by condition (ii); (d) is false, as the distance from D to E is 1
mile, E to C is ¼ mile and C to A is ½ mile, which is less than two miles. Hence (d).

54.c By conditions (vi) and (vii), choice (b) will make 2 roads coincide

55.b Diagrammatically, representing data in ques. and conditions (iv) and (v), J and H will
be ½ mile apart. Hence (b).
I
1 mile
J
0.5 mile
X
H one mile
G 0.5 mile

56.c As discussed in !. 117,
For answers to ques. 57 to 59: The provided info can be tabulated as follows:
Males Females
Name Profession Dress colour Name Profession Dress colour
A Electrician Brown Married to B Draper Black
C Lumberman Brown Married to E Television
star
Black
F Lumberman Grey/blue - D Electrician Blue/gray
Now, all the ques. can be answered.

57.c The married ladies are B and E.

58.b The married couples are AB and CE.

59.d The unmarried lady i.e., D wears a gray/blue coloured dress
For ques. 60
Sun Mon Tue Wed Thu Fri Sat
S No Play Q T U R P
Now, we can ans all the ques..


60.c No play is shown on Monday. Hence, (3)

61.a Play R is shown on Friday.

62.c The last play to be shown is P

63.b 2 plays are shown ranging from S and U
64.c ‘2’ is located on the eighth position.

65.b ‘a’ and ‘b’ are the two letters that are immediately preceded as well as followed by
numbers

66.c The 13th element from the right is ‘9’. 3rd to the right or ‘9’ is (2).

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Model ques. Paper Solution for CET Test as based on per Previous Year's Test
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