How To Exam?

# Bengal Engineering and Science University 2006 B.E Civil Engineering Surveying-II - Question Paper

Friday, 18 January 2013 06:05Web

ques. paper is in pdf format with attachment.

B.E. (Civil) 4th Semester Examination, May 2006 Sub: Surveying II (CE-401)

Full marks: 100    '    - ~    Time: 3 Hours

Assume any relevant data if necessary.

First Half

Answer question no. ONE and any TWO from the rest.

1.    Write short notes (any five)    (4X5=20)

ii.    Measurement of deflection angle

iii.    Telescope invert, Transiting and Changing Pivots

iv.    Consecutive coordinates and Independent coordinates

v.    Measurement of horizontal angle by reiteration

vi.    Bowditchs rule and Transit rule

vii.    Fixed Hair method and Movable Hair method

2.    (7+8=15)

(a)    What is Double Meridian Distance? Derive the rules for finding out Double Meridian Distance for

a traverse.

(b)    Following observations are made for a closed traverse.

 Line Latitude (m) Departure (m) AB -300 +400 BC +640 +160 CD +100 -300 DE -440 -260

Compute the area of the traverse by co-ordinate method.

3.    (5+10=15)

(a)    Describe how the accuracy of an open traverse is checked?

(b)    A straight tunnel is to be run between two points A and B, whose independent coordinates are:

Point    Independent coordinates

N    E

A    0    0

B    3014    256

C    1764 . 1398

It is desired to sink a shaft at D, the mid-point of AB, but it is impossible to measure along AB directly. So D is fixed from C, another point whose coordinates are known.

Calculate the

(i)    Independent coordinates of D

(ii)    Length and bearing of CD

(iii)    Angle ACD, given the W.C.B. of AC is 3824

4.    (5+10 = 15)

(a)    Derive the expression for horizontal distance using principle of stadia method.

(b)    Following observations were made by a tacheometer fitted with a anallatic lens having multiplying constants100.00.

 Instrument station Staff Station Vertical angle Staff hair reading (m) Remarks Lower Middle Upper P Bench Mark 5 2.00 1.50 1.00 Staff Inverted on B.M P Q -10 1.00 1.40 1.80 R Q -10, 2.00 3.10 4.10 R.L of B.M. = lOO.m

If the height of the instrument at P and R are 1 .Om and 1.5 m respectively and the staff held vertical find the reduced level of P, Q and R.

Second Half

Answer question no. FIVE, and any TWO from the rest.

(4X5=20)

5. Write short notes (any five)

Free haul and limit of economic haul

i.    Waste and Borrow

ii.    Multilevel section v. Compound curve and Reverse curve

v.    Centrifugal ratio and Cant

vi.    Nomenclature of a curve

vii.    Shift of the curve

6.

(7+8=15)

(7+8=15)

(a)    Deduce the expression for cross-sectional area for a Two-Level section.

(b)    State and prove the prismoidal formula for volume computation.

7. (a) Explain the main features of Mass Haul Diagram

(b) Following data were obtained for construction of a road-way section.

 Chainage (m) 0 10 20 30 40 50 60 70 80 90 100 110 120 130 Cut (m3) - 15 20 25 30 35 50 70 - - - - - - Fill (m3) 50 40 30 50 75 90

Complete the Mass Haul Diagram from the above data and find the distance up to which the cut and fill will be balanced.

8.    (7+8=15)

(a)    What is meant by a transition curve? Derive the expression for ideal transition curve.

(b)    A circular curve is to be designed to negotiate the vehicles from a transition curve to a circular curve with a speed of 40 km/hr. The maximum centrifugal ratio permitted on the road way is

0.25. Calculate the length of five offsets (except two tangent points) from the long chord and the chainages of the tangent points if the chainage of the intersection is 2500 m. Take the angle of intersection equals to 140. 