Jawaharlal Nehru Technological University Hyderabad 2010-1st Year B.Tech -\\Computer Science & Engineering\ regular\MATHEMATICs I set 1 - Question Paper
Code No: 09A1BS01 R09 Set No. 1
I B.Tech Regular Examinations,June 2010
MATHEMATICS-1
Common to ME, CHEM, BME, IT, MECT, MEP, AE, BT, AME, ICE,
E.COMP.E, MMT, ETM, EIE, CSE, ECE, EEE,CE
Time: three hours Max Marks: 75
ans any 5 ques.
All ques. carry equal marks
Code No: 09A1BS01 R09 Set No. 1
I B.Tech Regular Examinations,June 2010 MATHEMATICS-1 Common to ME, CHEM, BME, IT, MECT, MEP, AE, BT, AME, ICE, E.COMP.E, MMT, ETM, EIE, CSE, ECE, EEE,CE Time: 3 hours Max Marks: 75
Answer any FIVE Questions All Questions carry equal marks
Find the radius of curvature at any point on y2 = 4ax and hence show that the radius of curvature at the vertex is equal to the semi latus rectum.
1. (a (b
2. (a (b
3. (a (b
4. (a (b (c
5. (a (b
6. (a (b
7. (a (b
8. (a (b
Trace the curve r = a (1 + cos 0) [7+8]
Find the volume of Spherical cap of height h cut off from a sphere of radius a.
n a(1+cos 0)
Evaluate J J r2Cos0drd0 0 0
[8+7]
Solve the differential equation (D2 + D + 1)y = x3 Solve the differential equation (D2 + 1)y = sin x sin2x
[8+7]
Form the differential equation by eliminating arbitrary constants y = a x3 +bx2
Solve the differential equation x3 |f = y3 + y2\jy2 x2
Find the orthogonal Trajectories of the family of curves x2+y2 = a2 [4+6+5] If u = x2 2y,v = x + y + z, w = x 2y + 3z find
Find the maximum and minimum values of f (x) = x3 + 3xy2 3x2 3y2 + 4
[8+7]
Find the constants a and b so that the surface ax2 byz = (a + 2) x will be orthogonal to the surface 4x2y + z3 = 4 at the point (-1,1,2).
Evaluate (yzdx + xzdy + xydz) over arc of a helix x = a cos t,y = a sin t,z =
e
kt as t varies from 0 to 2n [8+7]
Find L
t
Solve the following differential equation using the Laplace transforms
df 2f + x = e2t with x(0) = 2, f = 1 att = 0 [8+7]
(n!)2x2n
Test the convergence of the series ( (2
V 5 l)
Test the convergence of the series vvra2+1
[7+8]
4
-k -k -k -k -k
Attachment: |
Earning: Approval pending. |