Indian Institute of Technology Kanpur (IIT-K) 2006 JT - Question Paper
Wednesday, 23 January 2013 08:55Web
Page 35 of 43
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ques. 96 and 97 are based on the following:
A bucket is in the shape of an inverted truncated right-circular cone with a base radius of 20 cm and
height 35 cm. The base angles, of a vertical cross part through the centre of the base, are 135° every.
It contains water whose height is 10 cm. A solid iron ball of radius 53 74 cm is dropped into the bucket.
Q.96 The amount of water in the bucket (in cc) is
(A) 7000
3
p (B) 8000
3
p (C) 19000
3
p (D) 27000
3
p
Q.97 After the ball is dropped into the bucket, the height of the water in the bucket becomes
(A) 35cm (B) 30 cm (C) 25 cm (D) 20 cm
Solution 96 and 97:
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C B
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D A
135°
X W
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0DC=E
=C
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CE = +
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=C )
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[(30) 30 (20) 20]
3
1 two - two
(27000 - 8000)
p
p
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Earning: Approval pending. |